Combinatorics problem (balls in bins)
Struggling currently with coming full circle on a problem. Given:
15 non unique bins n=15
6 non unique balls m=6
bins uniformly of size 4
What is the probability that 2 or more balls will end up in the same bin. Experimentally I know the result is about 59% and have the following formula to describe the situation
P(X>=2) = 1 - (((15c6)×4^(6))/(60c6))
However I am struggling with the derivation of the above, a breakdown from someone better at stats than I would be appreciated.
u/FROG_TM — 6 days ago