u/Flat-Fun-7298

Messing around with G and log

ζ_12: c_n^G = 96i·c_n^π² − (128√3/9)·c_n^L_{-3

So

2G= (3/4)·[Li_2(ζ_12)/ζ_12 + Li_2(ζ_12^5)/ζ_12^5] − (3√3·i/4)·[Li_2(ζ_12)/ζ_12 − Li_2(ζ_12^5)/ζ_12^5] + iπ²/48

So

3G = (3/4 − 3√3·i/4)·Φ_0(ζ_12) + (3/4 + 3√3·i/4)·Φ_0(ζ_12^5) + Φ_0(i)

Felt like a dirty combo

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u/Flat-Fun-7298 — 13 days ago