▲ 0 r/mathematics
Messing around with G and log
ζ_12: c_n^G = 96i·c_n^π² − (128√3/9)·c_n^L_{-3
So
2G= (3/4)·[Li_2(ζ_12)/ζ_12 + Li_2(ζ_12^5)/ζ_12^5] − (3√3·i/4)·[Li_2(ζ_12)/ζ_12 − Li_2(ζ_12^5)/ζ_12^5] + iπ²/48
So
3G = (3/4 − 3√3·i/4)·Φ_0(ζ_12) + (3/4 + 3√3·i/4)·Φ_0(ζ_12^5) + Φ_0(i)
Felt like a dirty combo
u/Flat-Fun-7298 — 13 days ago