Here are the answers for pure 1
- the equation was 9x+5y-7=0
coordinates of t were (8,-13)
area was 528/5
- question was to find the first and second derivatives
a) 5/2x^3/2 - 3/2x^1/2 - 3x^-1/2
b) 15/4x^1/2 -3/4x^-1/2 + 3/2x^-3/2
- surds question
k is rational and = 11/3
b)i) is sqrt 5 + 2 * sqrt 6
solving for x question, x is 5*sqrt 5 + 10 * sqrt 6
- cubic graph, the constant was -1/8 so the graph equation was -1/8(x^2)(x+3)
after the transformation it was (-5,0) and (-2,0)
- the a/b indices bullshit
in the first 3 we had to give it in kx^n form so
i)= 0.5x
ii) 81/16 x^2
iii) 9/8 x^3
and then the solutions are 1 and 4 since x>0
- integration, show that k= 3
b) integrating it, you get x^4 - 8x^2 + 3x + 1
c) equating (b) to 3x-15 and getting x= +- 2, taking -2 and getting q as (-2,-21)
sector, BC is 4.06
area is 3.93
the angle is greater than pi/2 was a trick, its greater than pi/2 anyway
- completing the sqaure
a) was 3(x-2)^2-5
coords of turning point are (2,-5)
inequalities are x>= 2
y<= line equation (dont remember)
and y>= 3(x-2)^2-5
discriminant question, the graph had asymptotes at x=2 and y=0 and cut the y axis at (0,-q/2)
the range of q where the 2 graphs dont touch are the solutions of q^2-16q+16 so its between 8-4root3 and 8+4root3
a) (3/2 pi,-4)
b)2pi/5
c) k=2.5
d) (pi,4)
e) k=30 since 15 solutions from 0-12pi and 2 solutions from 0-0.8 pi