Do the degenerate vacua in spontaneous summery breaking result in the same physical constants, regardless of which point on the brim the universe settles into?
I'm a little confused about spontaneous symmetry breaking. My understanding is that a universe initially in a symmetrical state (represented by a ball on the top of a Mexican hat) can eventually roll down to one of the points on the brim, and all the continuous points on the brim represent a possible point the universe can settle into. In terms of the physical constants, does it matter which one of those points (vacua) the universe settles into? Or are the physical constants and particle masses the same regardless?
To clarify, I'm asking this because the concept of vacuum states is also related to string theory, and the different vacuum states on the string theory landscape lead to different physical constants. Is this not the case when we're just talking about spontaneous symmetry breaking in a non-string theory sense?