u/dragonxsword

Could you guys check this?

Am I nuts or did I solve this?

Rules are flawed.

The divide by 2 on even number causes this loop.

Because 3x+1 or 3(1)+1=4 which is divisible by 2.

Because it means that ANY equation where X can equal 1, that hits a number divisible by by 2 will hit this loop eventually

For example, if you replace the first part with 7x+1. And this ruleset eventually hits a number divisible by 2 (which it eventually will). It will go down to 1.

1x7+1=8

8÷2=4

4÷2=2

2÷1=1

Repeats

Other examples this works on:

3X+5 (because 3(1)+5=8 so 8 will be loop

15X+1 (because 15(1)+1=16 so 16 will be loop

That being said, the higher numbers you use, the longer it will take for equation to hit breakpoint (divisible by 2) number.

Also, a more simple version of the equasion is technically 1x+1 which is 1(1)+1=2. So a loop starting at 2 after breakpoint. Or 2, 1.

And we know that 3X+1 loop 4 works. (4, 2, 1)

If we can prove that 7X+1 loop 8 works, and will eventually hit the breakpoint, it could be a breakthrough.

Could you all double check me?

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u/dragonxsword — 26 days ago