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Image 1 — Sunday, October 4, 2026 - Pips #413 Thread
Image 2 — Sunday, October 4, 2026 - Pips #413 Thread
Image 3 — Sunday, October 4, 2026 - Pips #413 Thread
Image 4 — Sunday, October 4, 2026 - Pips #413 Thread
▲ 6 r/nytpips

Sunday, October 4, 2026 - Pips #413 Thread

Post your results and commentary for today's puzzles.

(Depending on where you are in the world, the game number might be off, so match your puzzle to the images and post accordingly)

u/gluemanmw — 11 days ago
▲ 9 r/nytpips

10/4 H Walkthrough

Again there are multiple solutions, I'll do the easiest one which is different than NYT's.

  1. >!The bottom 2c3 has to be the 0-3, and the >5 above that is our only 6, 3-6 which must extend into the discard to not trap the 1c3!<
  2. >!At this point we can take stock of the pieces we have, we have three of 0s and 1s, five 2s and 4s, four 3s and 5s. 2-2 and 4-4 are our doubles.!<
  3. >!Since we don't have another piece valued at 3, the outer tiles of the top 2c3s point down into the 3c= and 1c2 respectively.!<
  4. >!There are two 1c2s, but we also need 2s for one of the 3c=s, therefore we have no 2s for the 2c3s, making both 0+3!<
  5. >!This means, with the purple 1c0, all 0s are effectively marked, and both <2s are 1!<
  6. >!What about the 5s, even if both discards are 5s, one must be in an =/= area because the 2c8 can accommodate just one; if the 2c8 is 4+4, then both discards are 5!<
  7. >!in the 2c8 is 3+5 scenario, we would have all the 3s booked as well: one in the 2c8, one each in the 2c3s, and a 1c3. Furthermore, the 2-4 is forced to the right bottom corner, meaning 1c0 is the 0-5 since at least one discard must be 5!<
  8. >!In the 2c8 is 4+4 scenario, the 4-5 is forced to the same corner, and the 1c0 is the 0-5!<
  9. >!Ergo we know that no matter what the 0-5 covers the 1c0!<

Branching starts here.

  1. >!Let's pretend the discards actually form a 2c10, it'll have to be split since we have no 5-5, both tiles "go up", placing the 0-5. The other tile has to be the 4-5 since it needs a digit with a double. 4-4 finishes up the right side 3c=, and 2-2 in the other one!<

  2. >!2-4 cannot be in the red 1c2 extending into the purple =/=, because that would make the 2c3 a single domino, the only other place it can go is the green 1c2 and 2c8. This would in turn force the 3-4 above it, and 0-2 in the left corner!<

  3. >!The 2-3 is forced into the red 1c2, and taking the 0-1 with it.!<

  4. >!3-5 can go in either the purple =/= or the 1c3, doesn't matter. And the other two pieces can go where ever!<

Very unsatisfying IMO.

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u/jxd73 — 12 days ago