r/nytpips

Image 1 — Thursday, May 21, 2026 - Pips #277 Thread
Image 2 — Thursday, May 21, 2026 - Pips #277 Thread
Image 3 — Thursday, May 21, 2026 - Pips #277 Thread
Image 4 — Thursday, May 21, 2026 - Pips #277 Thread
▲ 12 r/nytpips

Thursday, May 21, 2026 - Pips #277 Thread

Post your results and commentary for today's puzzles (Depending on where you are in the world, the game number might be off, so match your puzzle to the images and post accordingly)

u/gluemanmw — 22 hours ago
▲ 13 r/nytpips

May 21 hard solving guide

I posted the strategies and notation helper here.

Wow, this is hard.

As usual for puzzles like these we use a chessboard notation, A1 is a discard, F1 is a 5, A5 is a 0, F5 is also a 5.

Puzzles like these can be arena driven where we look at a tile and the available dominos and find only one domino can go on that tile or domino driven where we look at a domino and find it has only one place where it can go. This solution is 100% arena driven.

Major breakpoints where you could stop and enjoy figuring it out is after step 1, step 4, step 5. Step 2-4 is really one step I just broke it down for easier understanding. Step 5 is independent of the previous steps, it could be done earlier. Many orders are possible for the placement itself, the before section is the hard one.

Before placement >!except one!<:

  1. >!E1 can't go up as that'd be 1-1 so it goes left or right, either way the 1-5 is here.!<
  2. >!A3 can't go right as that'd be the 2-2.!<
  3. >!Let's presume A3 goes up, it's the 2-4. B4 goes right as well because down or up would be the same 2-4. Also A5 goes right. Now C5 is forced to the right which is the 1-5 but that's booked.!<
  4. >!So A3 goes down, it's the 2-0.!<
  5. >!There are five halves for each number, count the tiles on the board for each, three 3s and a 5 is missing. At most two 3s fit in the discard so one is in the 2c= that means the 2c= is 3s. The third 3 is in the discard, the other discard is a 5.!<

Placement:

  1. >!A4 goes up, 4-0: right? 4-4, doesn't exist.!<
  2. >!A1-B1 is 3-5.!<
  3. >!F5 goes left, 5-4: down? 5-3, used.!<
  4. >!D5 goes down, 5-0: left? 5-1, booked.!<
  5. >!F4 goes down, 3-0: left? 3-3, doesn't exist. (But also F3 goes up: left? 0-4. Down? 0-2. Both are used.)!<
  6. >!E4-E3 is 3-4.!<
  7. >!C4 goes up, 3-1: left? 3-4, down? 3-0. Both are used.!<
  8. >!B4-B5 is 4-2.!<
  9. >!B3 goes down, 2-3: right? 2-0, used.!<
  10. >!C3 goes right, 0-1: down? 0-2, used.!<
  11. >!C2 goes down, 2-1: right? 2-4, used.!<
  12. >!Place 4-1, 2-5 and the 1-5 last.!<

Note: >!the only place for 5-2 is on F1-F2 and so E1 goes left meaning the 5-1 is on D1-E1 from the very beginning but we didn't need to figure this out, it's enough the 5-1 is booked.!<

Also note >!you can't avoid solving the upper left corner because you can fill the board almost https://i.imgur.com/BxGrsVY.png with the only problem being A5 and B3 are not being next to each other so you won't find any other contradiction!<

u/chx_ — 1 day ago
▲ 11 r/nytpips

Wednesday, May 20, 2026 - Pips #276 Thread

Post your results and commentary for today's puzzles (Depending on where you are in the world, the game number might be off, so match your puzzle to the images and post accordingly)

u/gluemanmw — 2 days ago

Bug for May 19?

Check out the bottom left (<2 and 11) - none of the tiles meet this criteria.

u/ro8t — 2 days ago

Tuesday, May 19, 2026 - Pips #275 Thread

Post your results and commentary for today's puzzles (Depending on where you are in the world, the game number might be off, so match your puzzle to the images and post accordingly)

u/gluemanmw — 3 days ago

May 20 hard solving guide

I posted the strategies and notation helper here.

Different orders are possible but the logic remains the same. There are many solutions but they are all the same. I kept the counting to an absolute minimum.

  1. >!3c0 is three 0s, the 1c0 is the fourth, 0s are booked.!<
  2. >!With 0s booked, the 6c≠ contains one of each non-0.!<
  3. >!We only have one more counting step ahead of us, instead of counting, we will rely on doubles: 2-2, 5-5 and 6-6 exists, while 0-0, 1-1, 3-3 and 4-4 does not.!<
  4. >!If the middle tile of the 3c0 goes left or right it'd be the 0-0 which doesn't exist so it goes down into the 4c=.!<
  5. >!The right tile of the 3c0 can't go down as it would be the same as the previous one so it goes to the right. It can't be the 0-2 because you'd need another 0 in the 2c2 to finish it so it's the 0-1.!<
  6. >!The tile in the 4c= below the 2c2 now only has equal neighbours, it's one half of a double.!<
  7. >!Out of the 0-[2/3/4] only the 2s have a double. Place the 0-2 to the middle of the 3c0, the 4c= are 2s.!<
  8. >!The left tile of the 3c0 can't go left as it would be the 0-1 again, it goes down. There are only three 3s and so it can't be the 0-3 because there would be no 3 left for the 6c≠. It is the 0-4 marking the top 3c= for the 4s.!<
  9. >!The left 1c1 also goes down, the 2c12 is 6+6, so it's the 1-6.!<
  10. >!The last 0-?, the 0-3 can't go left because the other 3c= also can't be 3s so the 0-3 is on the 1c0-1c>2 border.!<
  11. >!If the bottom right of the top 3c= goes left it'd be the 4-4 which doesn't exist so it goes down into the other 3c=.!<
  12. >!The corner of the top 3c= can't go down as it'd be the same domino, it goes to the left, it's the 4-6.!<
  13. >!Now the the left two tiles of the bottom 3c= is a double, the other tile is the non-4 half of 4-[1/3/5] and only the 4-5 has a double so place it and the 5-5.!<
  14. >!The top tile of the 2c2 is a 1, the top 2c12 is also 6+6, so the top tile of the 2c2 can't go up because the 1-6 is used, it goes to the right into the 2c7.!<
  15. >!If the 2c2-2c7 is the 1-5 you'd need the 2-2 on the 2c7-4c= border but we know the 2-2 is in the 4c=, that's how we found the 4c= is 2s in the first place, so it's the 1-4.!<
  16. >!Place the 3-2 on the 2c7-4c= border.!<
  17. >!Finish the 4c= with the 2-2.!<
  18. >!Place the 6-6 in the top 2c12.!<
  19. >!Place the 1-5, 2-6, 3-4 into the 6c≠ any way.!<

Alternatively, with a bit more counting, I tried to not repeat any arguments except the very beginning:

  1. >!Same as before, we find the 0s are booked into the 3c0 and the 1c0 and the 6c≠ contains one of each non-0.!<
  2. >!Then the 0-3 is not in the 6c≠ but where is it? There isn't enough 3s for a 3c= much less a 4c=, the only neighbour of the 0s that can take a 3 is the 1c>2.!<
  3. >!Then where is the 4-3? If not the 6c≠ then the only place for the 3 half is the 2c7. If the 4 is in the 2c7 as well then the 6-6 is above it and the 2c2 can't be made because the 0-2 is booked and the 1-1 doesn't exist. If the 4 half is in the 4c= then all the 4s are booked into the 4c= and the 6c≠ and there isn't one more left to finish the 2c7. So the 4-3 is in the 6c≠.!<
  4. >!There's a 2 in the 6c≠, one of 2-[0/2/3/6] but the 2-0 is booked, the 2-2 is a double, the 2-3 would collide with the 3 from the 4-3, it's the 2-6.!<
  5. >!Then the last domino in the 6c≠ is the 1-5.!<
  6. >!Still, the only place which can take a 3 is the 2c7 so it's 3+4 and then there are only three 4s remaining.!<
  7. >!With that, the 4c= are 2s and all 2s are booked, nothing else has four of the same left.!<
  8. >!There are three 1s, one is in the 1c1, two 1s remain.!<
  9. >!The two 2c12 books all the 6s.!<
  10. >!The two 3c= are 4 and 5: the 0s are booked, two 1s left, the 2s are booked, the 3s have been placed, the 6s are booked.!<
  11. >!If the top 3c= are the 5s then the 5-5 is on the corner and then the middle tile of the bottom 3c= under it would be one half of a 4-4 which doesn't exist so the 5s are on the bottom and the 4s are on the top.!<
  12. >!If the 5-5 is on the right then the left tile of the 3c= would go up but there's no 5-6 so it's on the left.!<
  13. >!Finish the bottom 3c= with the 5-4.!<
  14. >!The 4-0 has nowhere else to go but the top of the top 3c=: the 0 can't be in any 2c12 and placing the 4 in the 2c7 would put the 0 in the 2c2 and then the 2c2 would need another 2 but all are booked into the 4c=.!<
  15. >!Place the 1-6 next to it.!<
  16. >!Place the 6-4 under it.!<
  17. >!Finish the 2c7 with the last 4-?, the 4-1.!<
  18. >!Place the 6-6 above it.!<
  19. >!Place the last 1-?, the 1-0 on the 1c1-4c0 border.!<
  20. >!Place the 2-2 under it.!<
  21. >!Finish with the 2-0.!<
reddit.com
u/chx_ — 2 days ago
▲ 10 r/nytpips

Monday, May 18, 2026 - Pips #274 Thread

Post your results and commentary for today's puzzles (Depending on where you are in the world, the game number might be off, so match your puzzle to the images and post accordingly)

u/gluemanmw — 4 days ago

May 19 hard solving guide

I posted the strategies and notation helper here.

Nice puzzle, lots of traps and misdirections but we chart a path without those. A little trial-and-error is needed but luckily nothing deep.

  1. >!Today every domino is horizontal instead of vertical.!<
  2. >!Start from the bottom right 4c=, the right hand is an equal, above it is a horizontal into the 2c9 and above that is a domino on the 2c2-2c9 border.!<
  3. >!Also, there'll be a domino on the 4c=-2c8 border and then this forces a whole domino into the 2c9 which is the 4-5 because the 3-6 doesn't exist.!<
  4. >!The available doubles for the 4c=s are 1-1,3-3,4-4,6-6 but there aren't enough 4s now so the two 4c= can be 1,3,6.!<
  5. >!If the vertical 2c9 is 3+6 then there are only three remaining of both which means one of the 4c= can't be made. So the vertical 2c9 is 4+5.!<
  6. >!Then the 2c9-2c2 is one of 4-[4/6] which are too high or 5-[1/3/6] and only the 1 is low enough so it's the 5-1.!<
  7. >!The top tile of the 2c9 is a 1, the bottom tile of the 2c9 is a 4.!<
  8. >!The remaining 4-? dominos are 4-[4/6] and only the 6 is candidate for 4c=. Place the 6-6 to the right.!<
  9. >!Place the 5-1 on the 2c9-2c2 border.!<
  10. >!Place the 6-5 on the 4c=-2c8 border.!<
  11. >!The bottom 2c8 is finished with a 3, three 3s remain.!<
  12. >!The top 4c= is now 1s, all other candidates are either placed or booked.!<
  13. >!Place the 1-1 to the left of the top 4c=.!<
  14. >!There will be two more 1s on the top, the last one is the top tile of the 2c2, the 1s are booked.!<
  15. >!The 2c8-3c8 border is one of 3-[1/3/5] but the 1 is booked, the 3-3 would need a domino with a sum of 6 but the non-1 dominos make 4 and 8 and not 6 so it's the 3-5.!<
  16. >!Finish the 3c8 with the 2-2.!<
  17. >!The 2c8 above it is the 4-4 now, the 3-5 is used.!<
  18. >!The only remaining non-1 domino is the 3-3, place it to the bottom of the 3c9.!<
  19. >!Place the 3-1 on the 3c9-2c2 border.!<
  20. >!The 1-0 is too low for the 4c=-1c>0 border so it's the 1-2.!<
  21. >!Finish with the 1-0 with the 0 in the discard.!<
reddit.com
u/chx_ — 3 days ago
▲ 12 r/nytpips

Sunday, May 17, 2026 - Pips #273 Thread

Post your results and commentary for today's puzzles (Depending on where you are in the world, the game number might be off, so match your puzzle to the images and post accordingly)

u/gluemanmw — 5 days ago

Puzzle suddenly deletes

Whenever a puzzle (like hard) is solved and I exit and come back, it shows that the puzzle is not solved yet. Coming back into it, the entire puzzle is gone, and the time remains the same from whenever it was solved (example: solving a hard in 2:03, the time then shows 2:03).

Just wanted to share

reddit.com
u/VeterinarianFront736 — 3 days ago
▲ 11 r/nytpips

Pips themed Connections game

Hello all, I made a custom Connections style game that is Pips themed

Just for funsies:

https://connectionsplus.io/game/OVQk3D

Enjoy...

EDIT -- If you are stumped here is the complete answer

u/Specialist_Class2980/comments/1tg9rca/answer_to_connections_pips_theme

....

You can create your own custom game as well. Can set it to Private, to share with family and friends - just send the link

https://connectionsplus.io

u/Specialist_Class2980 — 4 days ago
▲ 13 r/nytpips

Saturday, May 16, 2026 - Pips #272 Thread

Post your results and commentary for today's puzzles (Depending on where you are in the world, the game number might be off, so match your puzzle to the images and post accordingly)

u/gluemanmw — 6 days ago
▲ 10 r/nytpips

I wish I could play off-timer

Is there a way to play without running the timer? I struggle with the hard puzzle every day (I usually play all my NYT games at night). I’d love to be able to start the hard Pips earlier in the day and be able to leave and come back the way I do with Spelling Bee-to take a break and look at it with fresh eyes.
If I press pause, and leave the app (I play on my iPad), will my game stay paused until I get back?
I suppose I could try and see!
In general, I’m VERY slow compared to others in this thread. I usually get the Easy in < 1 min and the Medium in 3-6 min., though sometimes the Medium takes longer than the Hard, ha. But the Hard almost always takes me >10 min. and I almost always need hints.

reddit.com
u/Superb_Present5473 — 5 days ago

May 18 hard solving guide

I posted the strategies and notation helper here.

11-7=4. Nice. The puzzle is nice but not hard just a little tedious at the very end.

  1. >!1c<2 is either 0 or 1 but neither of 1-[0/2] fits the 1c>2 much less the 1c>4. So both 1c<2 is 0s.!<
  2. >!Then you have 0-[0/1/4/6] and only the 0-6 fits the 1c>4 and after that only the 0-4 fits the 1c>2.!<
  3. >!2c>11 is 12 which is 6+6, place the 3-6 on the 1c3-2c>11 border.!<
  4. >!2c11 is 5+6, place the 3-5 on the 1c3-2c11 border.!<
  5. >!6-2 is too low for the 1c>2 so finish the 2c11 with the 6-4.!<
  6. >!Finish 2c>11 with the last 6-?, the 6-2.!<
  7. >!With all the 6s gone, the whole domino at the top of the 3c14 is the 5-5. The next largest sum would be the 4-4 which is too low.!<
  8. >!The only 3c14 is finished with the only 4-?, the 4-4.!<
  9. >!There is a 3 in the last 1c3, two 3s remain.!<
  10. >!The top of the 3c= is a double, the available doubles are 3-3 and 0-0. There aren't enough 3s for a 3c= so it's the 0-0.!<
  11. >!Place the last 0-?, the 0-1 to the bottom.!<
  12. >!2c7 in theory is 1+6/2+5/3+4 but there are no 1s,6s,4s left so it's 2+5.!<
  13. >!The only 5 is the 5-2.!<
  14. >!If the 5-2 is on the 2c7-3c7 border then the 2c7 is finished with the 2-3 because the 2-1 is too low for the 1c>1 and the 3c7 needs a domino which has a total of 5 which is also the 2-3 so this is not possible.!<
  15. >!Place the 5-2 on the 2c7-1c>1 border with the 2 in the 1c>1.!<
  16. >!If the 2c7-3c7 is the 2-3 then you'd need a domino with a total of 4 to finish the 3c7 but the only ones are 3-3 making 6 and the 2-1 making 3. So the 2c7-3c7 is the 2-1.!<
  17. >!Finish the 3c7 with the 3-3.!<
  18. >!Place the 3-2 on the 1c3-discard border.!<

Note different orders are possible but they do not change the logic at all.

reddit.com
u/chx_ — 4 days ago
▲ 14 r/nytpips

Friday, May 15, 2026 - Pips #271 Thread

Post your results and commentary for today's puzzles (Depending on where you are in the world, the game number might be off, so match your puzzle to the images and post accordingly)

u/gluemanmw — 7 days ago

May 17 hard solving guide

I posted the strategies and notation helper here.

Important realization before placing: >!Much as it was yesterday, today every domino is vertical too. Start with the 2c10, the forced placement cascades to every domino.!<

The rest is easy. There are a lot of solutions.

  1. >!So there's a double in the right 3c= and another in the 2c=. The available doubles are 5-5 and 6-6.!<
  2. >!If the right 3c= is the 5-5 then the 3c=-2c9 is the 5-6, the 5-[0/2] are too low for the 2c9 but then the 2c9-1c0 needs to be the 3-0 which doesn't exist. So the double in the right 3c= is the 6-6 and the 2c= is 5-5.!<
  3. >!With the 5-5 gone, the 2c10 is the 4-6 either way.!<
  4. >!With the 6-4 gone, the right 3c= is finished with the 6-5, the 6-[0/2] are too low for the 2c9.!<
  5. >!The 1c0-2c9 is the 0-4.!<
  6. >!The 1c4 goes up, the 4-1 doesn't have enough for the 3c= so it's the 4-2.!<
  7. >!Place the 6-2 on the 1c6-3c= border.!<
  8. >!Place the 2-5 on the 3c=-2c10 border, the 2-3 is too low.!<
  9. >!Place the 5-0 on the 2c10-discard border.!<
  10. >!We have two 6s left, they are too high for 2c5 so one is in the discard, the other is in the 6c≠, this means the 1 from the 1-6 is in the 6c≠.!<
  11. >!The 1-4 now needs to be in the 2c5, it can go either way.!<
  12. >!Place the 2-3 in the 6c≠. Place the 1-6 and the 0-6 as well with one of the 6s in the discard, all of them are vertical, no other restriction.!<
reddit.com
u/chx_ — 5 days ago
▲ 14 r/nytpips

Thursday, May 14, 2026 - Pips #270 Thread

Post your results and commentary for today's puzzles (Depending on where you are in the world, the game number might be off, so match your puzzle to the images and post accordingly)

u/gluemanmw — 8 days ago
▲ 16 r/nytpips

Wednesday, May 13, 2026 - Pips #269 Thread

Post your results and commentary for today's puzzles (Depending on where you are in the world, the game number might be off, so match your puzzle to the images and post accordingly)

u/gluemanmw — 9 days ago

May 16 hard solving guide

I posted the strategies and notation helper here.

A new kind of puzzle, I liked it. Not too hard. Two solutions but not really.

Important realization before placing anything: >!every domino is vertical, start from say the bottom left, the 1c1 can only go up then that domino forces the 1c2 to go up and so on for the single cages up to the 1c5. Then the top half of the 2c= must go up which together with the domino on the 1c3-discard forces the domino above the 1c2-6c= to be vertical and so on.!<

The rest is easy.

  1. >!Place the 5-5 to the middle on the 1c5-1c5 border.!<
  2. >!The 6c= is 0s, nothing else has more than four much less six. One 0 remains.!<
  3. >!Place the 4-0 on the bottom 1c4-6c= border.!<
  4. >!Place the 2-0 on the bottom 1c2-6c= border.!<
  5. >!Above the 2-0 place the 0-0 fully in the 6c=.!<
  6. >!The bottom 1c1 is either 1-4 or 1-6 with the other half in the 2c=.!<
  7. >!If it's 1-4 then the 2c=-1c<3 needs to be the 4-2 and then the top 1c4 is the 4-3 but the 3 can't be on a 1c<3 so this doesn't work. The bottom 1c1 is the 1-6.!<
  8. >!The top 1c1 is the last 1-?, the 1-4.!<
  9. >!The bottom of the 2c9 is a 5, the only 5-? which fits a 1c<2 is the 5-0. It was the last 0, the 0s are booked.!<
  10. >!Place the 6-2 on the 2c=-1c<3 border, the 6-0 is booked.!<
  11. >!The remaining 0-?, the 0-3 and 0-6 are the two last 0s in the 6c=, the are on the 6c=-6c≠ border, either can be left or right of the 0-0.!<
  12. >!Above the 0-0 place the 2-5, the other dominos have a 3 half which is already present in the 6c≠.!<
  13. >!Place the last 2-?, the 2-3 on the top 1c2-discard border.!<
  14. >!The top 1c3-6c≠ can't be the 3-6 as a 6 is present in the 6c≠ already so it's the 3-4.!<
  15. >!Finish with the 3-6 on the bottom 1c3-discard border.!<
reddit.com
u/chx_ — 6 days ago