
Another Zimmerman-Traxler question
Hello,
Attached is an old exam question that I am struggling with. I believe I should go via a Zimmerman-Traxler transition state and since we have a trans enolate (11), I will end up with an anti aldol. However, no reactant that I have worked with prior has had such large groups attached to the carbonyl. I understand that the enolate reacts with the ketone and not the amide. I don't know how to determine the orientation of the ketone's substituents in 10 in the Zimmerman-Traxler. Which one will be pseudo-equatorial and which one will be pseudo-axial? Will the "amide side" be pseudo-axial, since there are 2 carbons until the bulky group as opposed to 1 (= less sterics)?
The exam question doesn't give a whole lot of points so I don't know if I'm complicating things here.
Thank you in advance!