I took the pKas value next to the Zwitterion or the neutral form of Aspartic acid, added them, and divided by two.
Would the correct number of sig figs be two sig figs? I was between three and two sig figs, but the question is based off of a molarity with two sig figs.
This is the addition of a strong base to a buffer solution, which increases the A- concentration, and decreases the HA concentration. We use Ka2 instead of Ka1 because our conjugate pair is SO32- and HSO3-, and those two are found the equilibrium equation that gives us Ka2.
I counted 8 total pi electrons since the lone pair on the nitrogen does not contribute. So therefore it would be anti aromatic since there an even number of pi electrons. If someone can check my answer please let me know, thank you!