u/Easy-Accountant2366

Ye sb jee mains pe aata h bhi?!

Btw controlled oxn pe 2 OH tutke H2C double bond kaise bn gya? Same smjh nhi aarha controlled oxn 3rd waale rxn mei

Why is hydroboration an anti-markovnikov addn? Here carbocation can undergo rearrangement aur hydride ion bhi udhar jaake judta so stable aata na rather thn anti markovnikov?

Krdo koi 🥀

Idhar 2nd step pe to OS03H bhi attack kr skta tha instead of OH- ?

Iss qs mei x=-8, 1/4 ko pura check krna hoga? Hum aese bol nhi skte ki lhs negative aa rha h jb x=-8 jo maine kiya?

Agr shayad +, - Or vice versa lhs mei rehta thn ig humko pura check nhi krna pdhta kyuki maybe LHS tb negative hota nd RHS as per corresponding value ke saath check krlete?!

Kya sahi bol rha hun ya nhi?!

11 nd 12 doubt.

No 17 pe ek btao ye racemixx kyu nhi banega?! Mera Optical iso mei racemix, stereoisomers baaki rehgya h.. Diaststereomers tk pdha tha!

Idhar to wedge product mei nhi banega na? Bcz like jb radical bn rha tha tb plane mei aagya i.e sp2 isliye?

Br2/hv 2 eq waale qs par coupling nhi hogi na?! Bcz acc to the mech of halogenation, sunlight ke presence mei X2 become 2X radical nd when we introduce the radical wrt to the hydrocarbon, tb jaake R radical bnti hai?!

Anyone confirm my logic?!

30,33 nhi bn rhe.. Will try thm again tho! 30 pe meri 11th krhb hai isliye dikkat aa rhi hai.. Also 30 pe agr like ef ko vert downward maanu to fir positive waali charge to max height pe ruk jaygi lekin negative pe to technically rukni chahiye kyuki accn opp hoga!

Studying circuits for first time exc 10th. I solved it correctly till the 3rd last step..

In the 3rd last step we can say that when current is divided into parts, the part in the negative y axis could also cover 3 ohm ndd 2 ohm such that they would be in series nd thn maybe we take 4 and 5 ohm as parallel.

Someone help me clarify what is wrong!!

44 mei D=0 dene pdh aesa kch aarha hai!!

Qs 33.

In no 11 should I compare the mag. ?!

Thn opt d hoga na?

4 wala doubt hai.

So we know ki a hollow sphere will keep it's charge distribution at its surface, so teachnically in the hollow sphere of radius A we get to see induced current developed in its surface, is that why it is opt a?!

Well I'm confused abt the radius of the hemispheres..

F = sigma times Area of hemisphere 1 nd sigma times area of hemisphere 2/ 4pi epsilon not..

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Detailed explanation plz.

Smjh nhi aarha options.

Iska kya kch aesa hoga?!