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u/Griffsterometer

r/TheSimpsons r/askmath r/mildlyinteresting r/xkcd r/PittsburghList r/betterCallSaul
▲ 5 r/PittsburghList

I want to film a music video in Pittsburgh. Don’t have any connections there, so I just need someone to hold the camera. $50 for an hour, $100 if you bring good video equipment

I wrote a song mentioning Pittsburgh that I’m releasing soon. I’m passing through town on Sept 2-3 and want to quickly film some footage for a music video while I’m there. If you’re free one of those days let’s figure out a time and place to meet up and film stuff for an hour. $50 if you film on a nice smartphone camera, $100 if you actually have a video camera we can use. Reach out if you’re down.

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u/Griffsterometer — 1 day ago
▲ 130 r/xkcd

Which xkcd changed your brain chemistry the most?

I personally think about 1741: Work at least once a week. I like to think it made me more appreciative by nature.

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u/Griffsterometer — 4 days ago
▲ 6 r/askmath

You play a game 100 times, choosing one of 20 difficulty levels each time. After 100 plays the game reports your win/loss ratio and the difficulty you chose most often. You want an impressive score at level 20, but you're not very good. What choices give a mode of 20 & minimize the mean difficulty?

Thought of this problem after misunderstanding the character stats page in Slay the Spire II. No actual use case, just thought it was an interesting problem. I wagered the optimal strategy involved splitting your choices evenly among some range of low options along with level 20. Here's what I tried so far:

  • Lvl. 1 - 49 plays
  • Lvl. 20 - 51 plays

(1 * 49) + (20 * 51) = 49 + 1020 = 1069

1069 / 100 = 10.69

  • Lvl. 1 - 33 plays
  • Lvl. 2 - 33 plays
  • Lvl. 20 - 34 plays

(1 * 33) + (2 * 33) + (20 * 34) = 33 + 66 + 680 + 779

779 / 100 = 7.79

  • Lvl. 1 - 25 plays
  • Lvl. 2 - 25 plays
  • Lvl. 3 - 24 plays
  • Lvl. 20 - 26 plays

(1 * 25) + (2 * 25) + (3 * 24) + (20 + 26) = 25 + 50 + 72 + 520 = 667

667 / 100 = 6.67

  • Lvl. 1 - 20 plays
  • Lvl. 2 - 20 plays
  • Lvl. 3 - 20 plays
  • Lvl. 4 - 19 plays
  • Lvl. 20 - 21 plays

(1 * 20) + (2 + 20) + (3 * 20) + (4 * 19) + (20 * 21) = 20 + 40 + 60 + 76 + 420 = 616

616 / 100 = 6.16

  • Lvl. 1 - 17 plays
  • Lvl. 2 - 17 plays
  • Lvl. 3 - 17 plays
  • Lvl. 4 - 17 plays
  • Lvl. 5 - 14 plays
  • Lvl. 20 - 18 plays

(1 * 17) + (2 * 17) + (3 * 17) + (4 * 17) + (5 * 14) + (20 * 18)

= 17 + 34 + 51 + 68 + 70 + 360 = 600

600 / 100 = 6

  • Lvl. 1 - 15 plays
  • Lvl. 2 - 15 plays
  • Lvl. 3 - 15 plays
  • Lvl. 4 - 15 plays
  • Lvl. 5 - 15 plays
  • Lvl. 6 - 9 plays
  • Lvl. 20 - 16 plays

(1 * 15) + (2 * 15) + (3 * 15) + (4 * 15) + (5 * 15) + (6 * 9) + (20 * 16)

= (15 * 15) + (6 * 9) + (20 * 16) = 225 + 54 + 320 = 599

599 / 100 = 5.99

  • Lvl. 1 - 13 plays
  • Lvl. 2 - 13 plays
  • Lvl. 3 - 13 plays
  • Lvl. 4 - 13 plays
  • Lvl. 5 - 13 plays
  • Lvl. 6 - 13 plays
  • Lvl. 7 - 8 plays
  • Lvl. 20 - 14 plays

(1 * 13) + (2 * 13) + (3 * 13) + (4 * 13) + (5 * 13) + (6 * 13) + (7 * 8) + (20 * 14)

= (21 * 13) + (7 * 8) + (20 * 14) = 273 + 56 + 280 = 609

609 / 100 = 6.09

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Based on these tests, I believe the minimum average while maintaining a mode of 20 is 5.99. Is anyone able to find a lower minimum, or prove that my answer is correct? Also, can this problem be extrapolated for x number of difficulties and y number of plays?

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u/Griffsterometer — 18 days ago