![[Grade 10] Quadratic equations - The values of 'a' for which the equations x³ - 6 x² + (6 + a)x - 6 = 0 and x²-ax+4=0 have a common root](https://preview.redd.it/p0inr2bsr42h1.jpeg?auto=webp&s=600848df5dd8976d8d5ad382d790cc6737b5a265)
[Grade 10] Quadratic equations - The values of 'a' for which the equations x³ - 6 x² + (6 + a)x - 6 = 0 and x²-ax+4=0 have a common root
I tried Combining the two equations given in the question, this resulted in
(a-6)x² + (2+a)x-6=0
x²-ax+4=0 (given)
These two equations have a common root alpha. USing Cramer's rule
(a²-5a+2)(2a-8)=(4a-18)²
a³-17a²+94a-170=0
How do I solve further? I am not able to calculate the roots of the cubic equation. Also acc to calculator there is only one real value of a that is 5. But the answer key says that there are three answers.
Also is there any other easier method to solve it??