u/PSGthe2nd

Attraction between 2 benzene rings | Organic Chemistry
▲ 2 r/Chempros+1 crossposts

Attraction between 2 benzene rings | Organic Chemistry

Hello, I was reading an article ref(pubs.rsc.org/en/content/articlepdf/2016/nr/c6nr00735j), wherein I encountered a doubt.

The construction

Basic overview, creating a diode using organic molecules.

So the thing is, when the whole setup is in positive Bias(i.e energy of R > energy of L) the molecules are attracted together. Here is citation from text:

>As the energy of the sites is different at zero bias, the current is low. For positive bias, the sites are pulled towards each other and the current increases. At 0.55 V, a pronounced peak is visible. This is the point where the two sites have equal energy and resonant transport occurs.

So, my doubt here is, in the line, "The sites are pulled towards each other" why? I realize that 2 F on ortho reduce the electron density in the benzene ring, herewith reducing its energy(i hope i got it right), so providing it with more voltage, helps bring this energy difference down and now suddenly the gap that is present(the ethane bridge), that gap is lost and effectively the pi orbitals of the 2 benzene rings are close enough so that resonance can take place, hence a forward bias.

Please help me with this.

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u/PSGthe2nd — 2 days ago
▲ 1 r/btech

College opportunities

Hello seniors.

I will be heading to college in next few months, can you please guide me a bit, and please let me know about oppourtunities?

Jaise ki there is GSoC, and probably the most famous one, but maybe tell me more about hackathons, and in general other fields like physics, chemistry, embedded systems and many more

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u/PSGthe2nd — 4 days ago

Choosing 3 squares along a diagonal line in a chess board | Combinatorics

Im sorry in advance if the flair is wrong. I couldnt find a suiting flair.

Here is the question:

The Question

Basically how I solved it, is dividing the chess board along diagnoal lines, then selecting 2 from them, and then multiplying it by 2 for no of favourable cases, i.e,

2( 8C3 + 7C3 + 6C3 + 5C3 + 4C3 + 3C3). Why? When you divide along diagonal line, the upper number represents the square in those diagonal lines, selecting 3 squares from there. Small squares tells me we select the smallest square unit. 2 because there can be 2 sets of diagonal ( IN X PATTERN)

But the solution says otherwise.

The Solution

Why is there 4 multiplied? I cannot understand it. Please help.

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u/PSGthe2nd — 13 days ago

The Question

We had to find the correct match for the following. What I thought is for (S) , the order should be option (1) because steric hinderance is least and symmetry(i dont know why i said that but I think it helps).

But the answer for S is option (4)

Also how is (P) decided? my thought says answer for (P) should be Q>R>P, since hinderance in P, then cis trans stability in Q,R

Also for option (Q), we can see that Q is always matched with (2), but that absolutely cannot be the case, because in P there would be intramolecular H bonding, which makes compound P least acidic.

For option (R), P>Q>R Since inductive effect.

But for the answer key, its option D, which I do not understand. Please help

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u/PSGthe2nd — 16 days ago

The question

Hello, while solving, I came across this,

Here is my attempt at solving it:
a) Pinnacol formation
b) Dehydration then rearrange then forming a ketone

The Solution

From here, clearly there's only 1 of this product(No Geometrical Isomerism, No Optical Isomerism)

But the answer is 2. Can you help me.

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u/PSGthe2nd — 16 days ago

Hello.
I was reviewing my test answers, when I got stuck in this question:

The question

In the answer key, it was given that its solved by claisen rearragement, so I reviewed it and tried solving it on my own, and ended up with this conclusion:

The Solution

I'll brief what I think happens. In the examples I found, they converted a benzene-ether to a substituted phenol. My understanding, that earlier the Oxygen had its lone pair restricted(i.e resonance will happen, but not that great since oxygen will accuire a positive charge, and it cant break any of its Carbon bonds so its a bit unfeasible) but upon taking the conversion, with phenol, it can freely resonate with the phenol, and the positive charge is no issue since it forms to a ketone like structure, H shifts to the -ve forming on the benzene ring, so on and so fourth. I'll link the reaction that I refered to below.

Here, I thought the same. Since ether is a bit restricted, converting it to ketone will help it tautomerize, increasing its stability(more "resonating" structures, hence higher resonance energy, hence higher stability).

This is why I formed the product. Can anyone correct me if I understood anything wrong??

PS:

The answer to the question is option (A)

Here is the reaction I reffered to online:

The Reaction

Thankyou

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u/PSGthe2nd — 21 days ago