Power Sums via CSN

Power Sums via CSN

My native language is not English, so I hope AI helps me make myself understood.

Brief summary about CSN in sums of powers:

From Knuth, we know that:

n^4 = 12 * S(n+2, 4) + (S(n+1, 2) = n^2)

where S(n, k) = C(n-1, k) + C(n, k).

The approach to express "any" sum of powers using the basis {C, S, N (Narayana numbers)} only requires elementary arithmetic and recognizing sequences.

For example, let's say we want to compute the sum of fifth powers (k^5):

We just multiply the sequences S(n+2, 4) and n^2 by n, which obviously gives us n^3.

We compute the terms of S(n+2, 4) = 0, 1, 6, 20, 50, ...

So: 0*1 = 0, 1*2 = 2, 6*3 = 18, 20*4 = 80, 50*5 = 250. Divide by 2 and we get 0, 1, 9, 40, 125. If we sum this sequence cumulatively, we get 0, 1, 10, 50, 175, which matches the first 5 terms of N(n+2, 4).

Therefore, the formula for SIGMA(k^5) = 24 * N(n+2, 4) + C(n+1, 2)^2.

IMPORTANT SECTION

I can predict all the initial coefficients (this is a conjecture), but once they reappear, it's no longer that easy.

This is where the concept of a "memory matrix" comes in: an array that contains all the coefficients that couple to the initial coefficients, making it possible to express any power sum.

In this matrix, I've noticed some interesting things:

The only non-trivial pattern in any diagonal or column appears in the second diagonal: the sequence 2, 10, 28, 60, 110, ... which is twice S(n+2, 3) = 1, 5, 14, 30, 55, ...

We can also observe an uneven growth pattern in the diagonals, where some terms grow faster than others. For example, in the second diagonal, the terms (2, 0, 0, -3, -11, 13/2) are always smaller than their two nearest terms, that is, compared to 1, 2, 10, 28, 60, 110.

Therefore, we can conjecture that, when taking absolute values, one subsequence of the diagonal shows slower growth compared to the other subsequence. This could be useful for generating coefficients by establishing upper or lower bounds.

Although there is no formula that generates all the coefficients of the matrix, its columns show the following asymptotic behavior in the limit as p goes to infinity:

Ratio (delta_11 / delta_9):

0 / 1 = 0

33 / 10 = 3.3

20 / 10 = 2.0

5733 / 1216 ≈ 4.714

15960 / 3419 ≈ 4.668

6473741 / 1377146 ≈ 4.700

70977060 / 15098484 ≈ 4.701

29913085305 / 6360805200 ≈ 4.702

Ratio (delta_11 / delta_13):

10 / 1 = 10

10 / 0 = undefined

1216 / 294 ≈ 4.136

3419 / 828 ≈ 4.129

1377146 / 349923 ≈ 3.936

15098484 / 3836868 ≈ 3.935

6360805200 / 1626520060 ≈ 3.910

So we have:

· The ratio column(delta_9)/column(delta_11) converges to 4.7

· The ratio column(delta_11)/column(delta_13) converges to 3.9

· The ratio column(delta_13)/column(delta_15) converges to 13.6

· The ratio column(delta_15)/column(delta_17) converges to 15.1

Thus, we can assume that the ratio between any pair of consecutive columns converges to a constant value.

Does this seem interesting to you?

u/PlentyBelt5048 — 8 days ago

Memory Matrix

Has anyone seen this matrix before, or am I dealing with mathematics that lies outside the literature? This matrix would be the analogue of the Bernoulli numbers, but in their arithmetic/combinatorial version; and, of course, it is related to sums of powers.

u/PlentyBelt5048 — 9 days ago

Cíclope indiferente

miles de ojos mirándote

el monstruo ansia tu arte

seras complaciente? entregate

seras consciente? sumérgete

elige Chéjov o Dostoyevski?

amarlo o ignorarlo?

no estas contento?

entonces apuñalate un ojo 🩸👁

tu ojo sano mira al monstruo

tu ojo sangrado es el abismo

usa tu sangre para hacer arte

usa tu indiferencia para mirarte

reddit.com
u/PlentyBelt5048 — 11 days ago

Cíclope indiferente

miles de ojos mirándote

el monstruo ansia tu arte

seras complaciente? entregate

seras consciente? sumérgete

elige Chéjov o Dostoyevski?

amarlo o ignorarlo?

no estas contento?

entonces apuñalate un ojo 🩸👁

tu ojo sano mira al monstruo

tu ojo sangrado es el abismo

usa tu sangre para hacer arte

usa tu indiferencia para mirarte

reddit.com
u/PlentyBelt5048 — 12 days ago

Sumas de Potencias vía CSN: Un Enfoque Aritmético

Hace unos días terminé de escribir mi propia investigación sobre matemáticas. Cabe aclarar que no soy matemático puro. El problema que intenté resolver (por mas de 2 años) fue el de las sumas de potencias de números naturales, utilizando una base de secuencias combinatorias. El enfoque que empleé para llegar a las fórmulas es muy elemental: literalmente se trata de aritmética e identificación de secuencias.

Les comparto mi texto y no duden en decirme qué piensan sobre él. Un saludo afectuoso desde México.

https://archive.org/details/spv-csn

u/PlentyBelt5048 — 13 days ago