I’m trying to figure out if hot acidified potassium dichromate reacts with the C=C double bond or only with alcohols in a molecule.
Hi guys, I’m trying to clarify something about the action of hot, acidified potassium dichromate (K2Cr2O7) in organic reactions.
I have this molecule:
CH3CH2CH=CHCH2CH2OH
So it has a C=C double bond in the middle and a primary alcohol at the end.
My question is: under hot acidified K2Cr2O7, what actually happens?
Does it:
- Break the C=C double bond and convert each carbon of the double bond into a C=O group (like ketones)?
- Only oxidises the alcohol at the end to a carboxylic acid, leaving the C=C completely untouched?
- Or does it break the C=C and produce carboxylic acids?
- Or does it do something else entirely?
I’ve seen conflicting sources online. Some say dichromate can cleave alkenes like KMnO4, others say it only reacts with alcohols/aldehydes. I just want to know what the expected standard reaction is in this kind of scenario.
Thanks in advance for any clear explanations!