got chem engg at main campus 13.8k rank T_T

i thought i wld get mech in r3 but didnt idk if its possible for r4 or shld i hope for intra? i have paid the fees for now might withdraw later as i also thinking of drop. should i rely on intra or r4? by when will we get know abt r4 or intra?

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u/Responsible_Rub_4093 — 5 days ago
▲ 2 r/mit_manipal+1 crossposts

how were opportunities for MS/UG Transfer abroad?

i have manipal ME as an option, should i take it for MS abroad like does manipal has good opportunities for the same and profile building for the same as well. the other option i have is to take a drop. what would you recommend seniors?

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u/Responsible_Rub_4093 — 9 days ago
▲ 2 r/mit_manipal+1 crossposts

i have abt 13.8k rank and i have a counselling doubt so help

I got chemical engg currently but can easily get ee blr or mech main campus easily in round 3 but i have paid 2.9L and got the provisional letter now how do i register for counselling in round 3 as i dont have any options to refill the choice lists. PLS SOMEONE TELL ASAP

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u/Responsible_Rub_4093 — 9 days ago

palindrome checker python i'm a beginner pls tell me why doesnt this code works on leetcode/geeksforgeek as it works on visual studio code. gemini says i am not defining things correctly and how do i learn the way gemini coded lol. also i am using angela yu's python course.

My Code: digits=[1,2,3,4,5,6,7,8,9]
print("Welcome to the Palindrome Checker!")
print("This program will check if a given string is a palindrome or not.")
number=int(input("Please enter a number to check: "))
number_list=[]
for digit_1 in str(number):
    number_list.append(digit_1)
print(number_list)
reversed_numberlist=number_list[::-1]
print(reversed_numberlist)
if number_list==reversed_numberlist:
    print("The number is a palindrome!")
else:    print("The number is not a palindrome!")
Gemini's code:
class Solution: def isPalindrome(self, x: int) -> bool: # Step 1: Handle edge cases # Negative numbers (like -121) and numbers ending in 0 (like 10) aren't palindromes if x < 0 or (x % 10 == 0 and x != 0): return False original = x reversed_num = 0 # Step 2: Math loop to reverse the integer while x > 0: last_digit = x % 10 reversed_num = (reversed_num * 10) + last_digit x = x // 10 # Step 3: Return True or False directly return original == reversed_num
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u/Responsible_Rub_4093 — 19 days ago
▲ 3 r/mit_manipal+1 crossposts

anyone thinking of partial?

i did saw many ppl willing to take partial earlier we connect as that will help us. I will most likely be taking EE/EEE/Mechx @ Main Campus.

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u/Responsible_Rub_4093 — 1 month ago