
u/Mr_anonymous_2008

ELON MUSK has officially becomes the first trillionare on paper , Do you think any unofficial trillionare are also there ?
The evm machine used in previous year are burnt in a fire incident , Any views on this 😶🌫️?
Can anyone explain properly, how light (photos) particles really copies information?
Like when light falls on a surface what really happens , like when it reflects back what it carries and what it copies ? , like it absorbs some colours and some reflect, that only the light carries which is responsible for our vision or anything bigger is happening?
My cbse friend was trying to know his crush's address, so as a good friend I found the adddress😅
So I have a friend who loves a girl from his very deep heart , he also made a drawing of her and gifted her in farewell, but one day we were roaming around, he told me about his fantasy that he wants to know his crush address, I asked why , he told me that I will send her a gift on her birthday, I said down , then I leave to home.
After comming to home , first I did a social media scanned ( public id ) , so I found that she was going to dance class from a very young age , so from there I got the academy name , then I r searched her phone no in Truecaller ( i think that no was her mother's no) , from there we got her mother's name and email, then I revered searched her mother's email, then i got google reviews of her mother which she post on dance academy, so lucky she from her personal email also commented on that , then we from instagram look up we got to know that her home was near with her dance class, so we have some idea about her locality.
Then for complete address we took the voter list from 2024 general election from ECI website then search her mother's name with her locality, so luckily we found her mother's name, and got exact pin point address.
Then I sent him the address he went completely mad , asking kaise kiya 😉. I gathered whole information from publically avilable data only . I used osint(open source intelligence) to get that address. At last he was very thankful to me 😅.
My cbse friend was trying to know his crush's address, so as a good friend I found the adddress
So I have a friend who loves a girl from his very deep heart , he also made a drawing of her and gifted her in farewell, but one day we were roaming around, he told me about his fantasy that he wants to know his crush address, I asked why , he told me that I will send her a gift on her birthday, I said down , then I leave to home.
After comming to home , first I did a social media scanned ( public id ) , so I found that she was going to dance class from a very young age , so from there I got the academy name , then I r searched her phone no in Truecaller ( i think that no was her mother's no) , from there we got her mother's name and email, then I revered searched her mother's email, then i got google reviews of her mother which she post on dance academy, so lucky she from her personal email also commented on that , then we from instagram look up we got to know that her home was near with her dance class, so we have some idea about her locality.
Then for complete address we took the voter list from 2024 general election from ECI website then search her mother's name with her locality, so luckily we found her mother's name, and got exact pin point address.
Then I sent him the address he went completely mad , asking kaise kiya 😉. I gathered whole information from publically avilable data only . I used osint(open source intelligence) to get that address. At last he was very thankful to me 😅.
I found out CBSE class 12 result of all students of my class (including my crush 🥰)
So for checking results of anyone, in cbse potal you need the students roll no, school no and admit card id. I have all students roll no because our class teacher has shared in our class group earlier. So my main problem is to find admit card id, If I able to guess then I can retrieve anyone result, roll no I have, school no is same for everyone. So first I call my close friend and told him to share his Admit card, then I started to analyse the admit card id then I noticed, me and my friend admit card id starts with A then a random letter (or Mother name last word) then roll no last 2 digit of roll no, then first 2 digits of my school no then middle 2 digits of center no, so for EX :
roll no: 14271267
school no: 36219.
Centre no: 918652
Then so I guess like first Digit A \\ {any alphabet or mother name last word) 67 (last 2 digits of roll no) then 36 (first 2 digits of school no) then 86 (2 middle digits of center no).
So admit card id I found A\\\_673686
So then I started brute force cbse website like I tried alll combination like AA673686,
AB673686 till AZ673686.
So by this I can able to take out 10 students result, but remaining 20 don't have this pattern, then I started to get into deeper then I Got to know that everyone in our class has last 4 digits common (because center no and school no is same for everyone in our class)of admit card id , and i already have roll no also of every student
So I need to guess first' 2 digits of which I conform that there are aphabets so
So 673686. But if I try every combination there will be 26 \\\* 26 = 676 combination I have to try
Then I student with sure name like Birst, Singh, Bairagi
Then I use last 2 digit of surname in admit card id.
Magically it worked, so by this trick I able to find most of students result, but for some students (5-8) this true also fail, so only option to try all 676 combination,
Then I thought and made a py program which ask students name and last \\\\\_\_ (last 2 digit of roll no, like for eg take 87) then 3686 (which is common for all students), then it automatically check all possibilities from AA873686 to ZZ873686 and stop at result (in cbse website) you can just start program and do some incial steps then leave it it automatically stops at result in cbse potal)
So by this all way I was able to take out every student CBSE Result of my class.
I started this to take out my crush result (which I finally got💘), and finally end up in retrieving everyone result.
so here i will demonstrate how my code works and to setup, use Firefox browser (recommended) because i made this code according to Firefox, update suffix in code = last 2 digits of roll no + first 2 digits of school + middle digits of center no, if you are checking result of your classmate then you and your classmate should have same last 4 digits of admit card so in this case you put suffix = last 2 digits of target roll no + same 4 digits, for full context read my previous story which is posted on this.
And this code is last option, first use surname name
technique (see previous post to understand full context). There are some other method which are fast but i made this code myself and it simple and safe. If you found this useful then comment. And if you want first follow then dm me i will send py code. After running code leave it it will check all possible ids From AA to ZZ, it will take time, Something the AA one combination often got skipped so check it manually once, and all combinations will be check and program will stop at result, means you can start code and leave it and come back after some time then you will find result. To understand full context read my previous post once. DM me if you want code.
Suggestion to get college
I got 59 in jee mains and 81 % in boards ( which is is not very useful) can you please suggest a Good college, I am seeing Newton school of technology as my future, is this college is good or just a hype , at 59 percentile I didn't see any option, my home state is delhi and ews .
Asking for college suggestions and review about Newton school of technology
I got 59 in jee mains and 81 % in boards ( which is is not very useful) can you please suggest a Good college, I am seeing Newton school of technology as my future, is this college is good or just a hype , at 59 percentile I didn't see any option, my home state is delhi and ews .
Regarding Cuet 28 May Exam postponed
Earlier my cuet exam was on 28 may, and nta suddenly postponed it and now some students have their exam on 31 may, 5/6 june, on 3 june I am going out of station, now I have to cancel my tickets which will further in deduction of cancellation fee, will nta will bare this loss, and most importantly it about mental peace, if you already know that 28 will eid then why the hell you schedule exam on that day.
May student have centres in different cities, they arranged their living facilities near the centre and ans may are going to their home after 28 (they already booked tickets) who will be responsible for this. Will you refund the money no you will not. Many students have also booked flight on 29/30/31 for going home. Many students also planed trip in june. I heard my student have other entrance exams also, what if the cuet exam that exam clase, you are literally playing with students future. At starting I was preparing, now I am thinking that how will I attend the exam, Shame on you nta.
I found out CBSE class 12 result of all students of my class (including my crush 🥰)
So for checking results of anyone, in cbse potal you need the students roll no, school no and admit card id. I have all students roll no because our class teacher has shared in our class group earlier. So my main problem is to find admit card id, If I able to guess then I can retrieve anyone result, roll no I have, school no is same for everyone. So first I call my close friend and told him to share his Admit card, then I started to analyse the admit card id then I noticed, me and my friend admit card id starts with A then a random letter (or Mother name last word) then roll no last 2 digit of roll no, then first 2 digits of my school no then middle 2 digits of center no, so for EX :
roll no: 14271267
school no: 36219.
Centre no: 918652
Then so I guess like first Digit A \ {any alphabet or mother name last word) 67 (last 2 digits of roll no) then 36 (first 2 digits of school no) then 86 (2 middle digits of center no).
So admit card id I found A\_673686
So then I started brute force cbse website like I tried alll combination like AA673686,
AB673686 till AZ673686.
So by this I can able to take out 10 students result, but remaining 20 don't have this pattern, then I started to get into deeper then I Got to know that everyone in our class has last 4 digits common (because center no and school no is same for everyone in our class)of admit card id , and i already have roll no also of every student
So I need to guess first' 2 digits of which I conform that there are aphabets so
So 673686. But if I try every combination there will be 26 \* 26 = 676 combination I have to try
Then I student with sure name like Birst, Singh, Bairagi
Then I use last 2 digit of surname in admit card id.
Magically it worked, so by this trick I able to find most of students result, but for some students (5-8) this true also fail, so only option to try all 676 combination,
Then I thought and made a py program which ask students name and last \\__ (last 2 digit of roll no, like for eg take 87) then 3686 (which is common for all students), then it automatically check all possibilities from AA873686 to ZZ873686 and stop at result (in cbse website) you can just start program and do some incial steps then leave it it automatically stops at result in cbse potal)
So by this all way I was able to take out every student CBSE Result of my class.
I started this to take out my crush result (which I finally got💘), and finally end up in retrieving everyone result.
I found out CBSE class 12 result of all students of my class ( including my crush 🥰 )
So for checking results of anyone, in cbse potal you need the students roll no , school na and admit card id . I have all students roll no because our class teacher has shared in our class group earlier. So my main problem is to find admit card id, If I able to guess then I can retrieve anyone result, roll no I have , school no is same for everyone. So first I call my close friend and told him to share his Admit card , then I started to analyse the admit card id then I noticed, me and my friend admit card id starts with A then a random letter ( or Mother name last word ) then roll no last 2 digit of roll no , then first 2 digits of my school no then middle 2 digits of center no , so for EX :
roll no : 14271267
school no : 36219.
Centre no : 918652
Then so I guess like first Digit A \_ { any alphabet or mother name last word ) 67 ( last 2 digits of roll no ) then 36 ( first 2 digits of school no ) then 86 ( 2 middle digits of center no ).
So admit card id I found A\_673686
So then I started brute force cbse website like I tried alll combination like AA673686 ,
AB673686 till AZ673686.
So by this I can able to take out 10 students result, but remaining 20 don't have this pattern, then I started to get into deeper then I Got to know that everyone in our class has last 4 give digits common ( because center no and school no is same for everyone in our class) , and i already have roll no also of every student
So I need to guess first' 2 digits of which I conform that there are aphabets so
So \_ \_ 673686. But if I try every combination there will be 26 \* 26 = 676 combination I have to try
Then I student with sure name like Birst , Singh , Bairagi
Then I use last 2 digit of surname in admit card id. Magically it worked , so by this trick I able to find most of students result, but for some students ( 5 - 8 ) this true also fail , so only option to try all 676 combination,
Then I thought and made a py program which ask students name and last \_ \_ ( last 2 digit of roll no , like for eg take 87 ) then 3686 ( which is common for all students) , then it automatically check all possibilities from AA873686 to ZZ873686 and stop at result ( in cbse website) you can just start program and dp some incial steps then leave it it automatically stops at result in cbse potal )
So by this all way I was able to take out every student CBSE Result of my class ,
I started this to take out my crush 🥰 result ( which I finally got 💘 ) , and finally end up in retrieving everyone result.