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Scorched 'WAGO?' 222 connector in lighting loop.
▲ 6 r/ElectriciansUK+1 crossposts

Scorched 'WAGO?' 222 connector in lighting loop.

Bought and moved into a new house, every room is lit by multiple 12V MR16 50W halogen lights (46 in total). Decided to replace with GU10 lamps and 5W LED bulbs. Each light has its own transformer to convert down to 12V from 230V.

So started to get rid of the transformers and MR16s to wire the GU10s straight into the 230V loops that are already there and found two 'WAGO' (possibly knock offs) just being used to chain earths like this.

The earths have been chained round with the live and neutral but not used for the previous MR16 (assuming because they're lower voltage and double insulated with the transformer??)

I was going to earth the GU10s seeing as theyre 230v and mounted on class 1 fittings.

But can't figure out why this would happen as the earth have just been chained round but not used?? Seems historical. Maybe historical faulty wiring? Possibly damaged externally from the heat of the halogen bulbs as they havent been properly encased?

Any ideas or suggestions would be appreciated.

u/Queasy_Fig_803 — 11 days ago
▲ 0 r/ElectriciansUK+1 crossposts

Undercut

Hope this is OK to post, admins feel free to remove if not.

I got fed up checking five merchant sites every time I priced a job, so I built a website that does it for you (undercutrade.co.uk)

Put in an item or a whole materials list and it shows the cheapest UK supplier, price per metre or per unit, ex or inc VAT. When I checked today, 100m 2.5mm cable was £41.69(42p p/m)at the cheapest place and £114.99(£1.15 p/m)at the dearest.

It's brand new, so I'm after honest feedback from people who actually buy this stuff:

  1. Did it find what you searched for?
  2. Were the prices right?
  3. What would make you actually use it?

Not trying to sell anything, the main bits are free. Rip it apart in the comments 😂

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u/K_theconqueror — 11 days ago
▲ 2 r/ElectriciansUK

I'm having my downstairs re-floored and want to put some cables in for a future EV charger. Just wanted to confirm I've chosen the right cables.

Whilst the floor is up, I'm going to put the cable down.

Don't know what EV or charger yet, but ordered 6mm2 twin & earth cable for a 32A / 7kW charger at some point in the future. Run is about 10m. Cable will be clipped to wooden suspended floor without insulation.

It's not going outdoors, and I'm going to wrap the cable up on both ends (one by the meter, one by the exit point of the house). Will obviously get pro to install the charger when I get it fitted.

Just checking a 6mm2 twin and earth (and separate cat6 cable) is suitable? And also whilst I'm at it a 4mm2 twin and earth for a future multisplit airconditioning

I was going off https://intrelec.co.uk/2020/10/21/cable-sizing-charts/

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u/langdalenerd — 12 days ago
▲ 2 r/ElectriciansUK+1 crossposts

Twin&Earth Cable underground

Hi, the power to my garage is supplied by pvc cable that goes under the decking and then is buried about 2 feet underground to the garage, total length about 35 feet. It’s been there with no problems for about 25 years…Question is should I replace with armoured cable or just leave it as it’s been ok for all this time? Tia

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u/hey-london — 12 days ago
▲ 1 r/ElectriciansUK

Need help in level 3 design project

​

Hello,

I'm struggling in question 5 of assignment number 615, and I need help figuring out where my mistake is. So here is a breakdown of what I have done, Step by step.

The question is: Determine, for one of the circuits supplying the fridges, the minimum possible cross sectional area of cpc which will satisfy the requirements disconnection as ADS under earth fault conditions and the adiabatic

equation as Regulation 543.1.3 in BS 7671.

Here is my attempt at it:

Step one - Table I1 in the onsite guide, the R1+R2/metre for a 4mm2 line conductor and a 4mm2 protective conductor is 4.61 R1+R2/metre + 4.61 R1+R2/metre = 9.22 R1+R2/metre

Step two - using the formula, from book 2 of electrical installations page 313, R1+R2 = R1+R2/metre × length × I3 factor / 1000

R1+R2 = 9.22 × 2.25 × 1.2 / 1000 = 0.0249

R1+R2 = 0.0249

Step three - Zs = Ze + (R1+R2)

Zs = 0.11 + 0.0249 = 0.1349

Zs = 0.1349

Step four - I = U/Zs

230/0.1349 = 1704.97

Step five - using the Adiabatic equation

√(I²)×t/K=s

√(1704.97²) × 0.1 / 115 = 4.69

Step six - Choosing the suitable CPC size would be 6mm2

The line conductor size is 4mm2, and the length of the circuit is 2.25 metres.

I'm really struggling to find my exact mistake, and I would really appreciate any help. Thank you all.

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u/joblesdude — 11 days ago